5y^2-2y+4=0

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Solution for 5y^2-2y+4=0 equation:


Simplifying
5y2 + -2y + 4 = 0

Reorder the terms:
4 + -2y + 5y2 = 0

Solving
4 + -2y + 5y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.8 + -0.4y + y2 = 0

Move the constant term to the right:

Add '-0.8' to each side of the equation.
0.8 + -0.4y + -0.8 + y2 = 0 + -0.8

Reorder the terms:
0.8 + -0.8 + -0.4y + y2 = 0 + -0.8

Combine like terms: 0.8 + -0.8 = 0.0
0.0 + -0.4y + y2 = 0 + -0.8
-0.4y + y2 = 0 + -0.8

Combine like terms: 0 + -0.8 = -0.8
-0.4y + y2 = -0.8

The y term is -0.4y.  Take half its coefficient (-0.2).
Square it (0.04) and add it to both sides.

Add '0.04' to each side of the equation.
-0.4y + 0.04 + y2 = -0.8 + 0.04

Reorder the terms:
0.04 + -0.4y + y2 = -0.8 + 0.04

Combine like terms: -0.8 + 0.04 = -0.76
0.04 + -0.4y + y2 = -0.76

Factor a perfect square on the left side:
(y + -0.2)(y + -0.2) = -0.76

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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